Type Challenges Judge

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Concat

提出詳細

type Concat<T extends any[], U extends any[]> = […T, …U];
提出日時2022-08-29 10:13:35
問題Concat
ユーザーyotarotsukada
ステータスWrong Answer
テストケース
import type { Equal, Expect } from '@type-challenges/utils'

type cases = [
  Expect<Equal<Concat<[], []>, []>>,
  Expect<Equal<Concat<[], [1]>, [1]>>,
  Expect<Equal<Concat<[1, 2], [3, 4]>, [1, 2, 3, 4]>>,
  Expect<Equal<Concat<['1', 2, '3'], [false, boolean, '4']>, ['1', 2, '3', false, boolean, '4']>>,
]